Square ABCD has a side length of 1. Point E lies on the interior of ABCD, and is on the line AC such that the length of AE is 1. Find the shortest distance from point E
to a side of square ABCD.

  1 -(√2)/2 ≈ 0.292893

Step-by-step explanation:

The diagonal length AC is √2, so the distance EC is √2 -1. That is the diagonal of the square whose side length is the length of interest. That side length will be (√2)/2 times the length of EC.

  shortest distance from E = (√2 -1)(√2)/2 = 1 -(√2)/2

step-by-step explanation:

pentagon

step-by-step explanation:

the coordinates   a(5, -2), b(3,-1),c(-4,-4) d(-3,8) and e(-1,4) forms the vertices of the polygon when they are connected in order.

in order to classify that which polygon is it with the given coordinates, first count the number of vertices and then count the number of sides it can make with these vertices.

since, the given coordinates have five vertices, therefore, it will make five sides. moreover, pentagon is regular in nature therefore it will be convex.

now, a polygon with five sides is known as pentagon, therefore, the given polygon is the pentagon.