A car of mass 800kg collides with a truck of mass 5000kg traveling at 40m/s. The car is thrown on to bonet of the truck which continous to more after impact at 10m/s in the original direction .How fast was the car moving.

177.5 m/s   (*)

Step-by-step explanation:

Applying the conservation of momentum for elastic collisions, with:

m1 = mass of car: 800 kg

v1  = velocity of car (unknown)

m2= mass of truck: 5000 kg

v2 = velocity of truck -40 m/s (opposite direction with car)

v2' = velocity of truck after collision =  -10m/s (opposite direction with car)

=> m1 x v1 + m2 x v2 = (m1 + m2)v2'

=>  800 x v1 + 5000 x (-40) = (800 + 5000) x (-10)

<=>800 x v1 = 200000 - 58000

<=> 800 x v1 =142000

<=> v1 = 177.5 m/s

This result looks like unreal.

In fact, it would be more reasonable if the velocities of truck before and after collision are 40km/h and 10km/h respectively. Hence, the result is 177.5 km/h.

Hope this helps!

to plot points   for x just start at the origin (middle) and go to the left however many times it say(if the number is a positive) if the number is a negative then go right however many times it says if it is 0 go nowhere

now keep you pencil there and go up however many times it says on y(if it is positive) if it is negative then go down however many times it says. if it says 0 go nowhere.

you have just plotted a point! now when you finish plotting all of them connect them with a ruler

plot each point as (-3, 7), (0,4), (3,1), (8,-4)   in the parenthesis on the left of the comma is x and the right is y.

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11