What are the solutions of x^2+3x-4=0

x = - 4, x = 1

Step-by-step explanation:

x²+3x-4=0

- 4 = 4*(-1)

3 = 4 + (-1)

(x + 4)(x - 1) = 0

x + 4 = 0, x - 1 = 0

x = - 4, x = 1

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.