Suppose that receiving stations X, Y, and Z are located on a coordinate plane at the points (6,2), (negative 2,negative 4), and (negative 10,4), respectively. The epicenter of an earthquake is determined to be 5 units from X, 5 units from Y, and 13 units from Z. Where on the coordinate plane is the epicenter located?

  (2,-1)

Step-by-step explanation:

A graph is useful here. Points X and Y have coordinate differences of ...

  X -Y = (6, 2) -(-2, -4) = (6+2, 2+4) = (8, 6)

Then the distance between X and Y is ...

  d = √(8² +6²) = √100 = 10

The point 5 units from X and from Y is the midpoint of XY:

  E = (X +Y)/2 = ((6, 2) +(-2, -4))/2 = (4, -2)/2 = (2, -1)

The epicenter is (2, -1).

_____

The graph shows circles of radius 5 around X and Y, and a circle of radius 13 around Z. The circles intersect at the point (2, -1), the epicenter.

answer: a

step-by-step explanation:

if xy ~ yz therefore xy would be the same length as yz

it's both, now can you answer my most recent question?