12 balls numbered 1 through 12 are placed in a bin. In how many ways can 3 balls be drawn, in order, from the bin, if each ball remains outside the bin after it is drawn? URGENT!

1320

Step-by-step explanation:

There are three "spots" for balls.

__ __ __

For the first "spot," and without replacement, meaning we don't put the balls back, there are 12 choices.

12 __ __

But for the next spot, there are only 11 choices. And for the next, there are only 10!

12 11 10

Since these are independent events, we multiply them together.

12 x 11 x 10 = 1320

There are 1320 possibilities!

How could we do it on the calculator, much faster? The question says "in order," so we know it's a permutation, not a combination. This is the nPr button on the calculator (math -> prb -> 2). Just type in 12 nPr 3 and you get the same answer, 1320.

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation:

11.2

step-by-step explanation:

when doing tangent the tangent of the angle is equal to the opposite side from the angle over the adjacent side to the angle.

tan43 = x / 12

move 12 over by multiplying each side by 12

12tan43 = x

x = about 11.2