Find the area of a triangle, two sides of which are 10 cm and 16 cm and the perimeter is 38 cm.

perimeter of triangle=a+b+cbut first we have to find the value of the third sideso here, a=10 b=16 c=xnow, 10+16+x=38 26+x=38 x=38-26 x=12area of triangle= 1/2×base×height = 1/2×16×9(height = 9 ,but why??here it is,using Pythagoras theorem, m²-1=8 m²+1=10so, m=9)continuation: =8×9 =72the area is 72 cmhope it helped :-)