A box has a base of 12 inches by 12 inches and a height of 30 inches. What is the length of the interior diagonal of the box? Round to the nearest hundredth. Enter your answer in the box.

36.50 in

Step-by-step explanation:

The length of the diagonal of the square base is found using the Pythagorean Theorem:  d^2 = (12 in)^2 + (12 in)^2, or d = √2*(12 in), or d = 12√2 in.

We use the Pythagorean Theorem again to find the length of the interior diagonal of the box:

[12√2 in]² + [(12 in)² + (30 in)² = (interior diagonal)²

This works out to   (interior diagonal)² = 288 + 144 + 900  inches², or

(interior diagonal)² = 1332 in²

Then the interior diagonal is √1332  in, or  approximately 36.50 in.

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

the solution is 12x-6y