a box contains several slips of paper. on each slip is written an odd number between 10 and 20. without looking you draw One slip of paper. find the sample space for this experiment.

We need to remember that the sampling space is the set of the possible outcomes for an experiment.

For this case we have a box and we know that the result for several flips is an odd number between 10 and 20 and then we can define the sampling space like this:

And the size of the sampling space is 5 elements.

Step-by-step explanation:

We need to remember that the sampling space is the set of the possible outcomes for an experiment.

For this case we have a box and we know that the result for several flips is an odd number between 10 and 20 and then we can define the sampling space like this:

And the size of the sampling space is 5 elements.

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v