Please help, i need to raise my grade
solve for v

2(s-c)/ a^2 =  v

Step-by-step explanation:

s = 1/2 a^2 v+c

Subtract c from each side

s -c = 1/2 a^2 v+c-c

s-c = 1/2 a^2 v

Multiply each side by 2

2(s-c) = 2* 1/2 a^2 v

2(s-c) = a^2 v

Divide each side by a^2

2(s-c)/ a^2 = a^2 v /a^2

2(s-c)/ a^2 =  v

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180