For z1=9cis(5π/6) and z2=3cis(π/3), find z1/z2 in rectangular form. A. -3

B. 3

C. -3i

D. 3i

D) 3 i

Step-by-step explanation:

Step(i):-

Given  Z₁ = 9 Cis ( 5π/6) = 9 ( Cos (5π/6) +i Sin (5π/6))

          Z₂ = 3 Cis ( π/3) = 3 ( Cos (π/3) +i Sin (π/3))

  Now  Cos (5π/6) = cos (150°) = cos(90°+60°)   = -sin 60 =

           Sin (5π/6) = Sin (150°) = Sin(90°+60°)   = Cos 60 =

    Z₁  = 9 ( Cos (5π/6) +i Sin (5π/6))

   Z₂ = 3 ( Cos (π/3) +i Sin (π/3))    

Step(ii):-

Rationalize with 1 - i √3 and we get

on simplification , we will use formulas

i² = -1 and    (a+b)(a-b) = a² - b²

Final answer:-

D. 3i

Step-by-step explanation: I got this right on Edmentum.

it's d.

step-by-step explanation:

because: -1(4x + 1y) +2 (1x-3y) distribute each number into the parenthesis.

then you would get: -4x - 1y + 2x -6y combine like terms

and get: 2x -7y

hope my answer has you if not then i'm sorry.

b

step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.