Please help! Is it 0.0364? Trudy has a collection of 11 dice, 4 of which have twelve sides.
If Trudy randomly rolls 4 dice in a specific order, what is the probability that just the first 2 of the chosen dice have twelve sides?

Write your answer as a decimal rounded to four decimal places.

0.0636

Step-by-step explanation:

The probability the first die has twelve sides is 4/11.

The probability the second die has twelve sides is 3/10.

The probability the third die does not have twelve sides is 7/9.

The probability the fourth die does not have twelve sides is 6/8.

The probability of all four events is:

4/11 × 3/10 × 7/9 × 6/8 = 0.0636

answer: the two figures are congruent.

step-by-step explanation: they're congruent because figure efgh is reflected across the x and y axis but it was also rotated.

hope it !

-1/2 +2

step-by-step explanation: