∆ABC is reflected across the x-axis, then rotated 90° clockwise about the origin, and finally reflected across the line y = x to form ∆A′B′C′. The coordinates of vertex A′ are . The coordinates of vertex B′ are . The coordinates of vertex C′ are .

Step-by-step explanation:

Notice that the vertices are A(1,1), B(2,3) and C(2,1).

A reflection across the x-axis give the coordinates A'(1,-1), B'(2,-3) and C'(2,-1). Then, we apply the rotation 90° clockwise about the origin A'(1,1), B'(3, 2) and C'(1, 2).

Finally, a reflection across the line y = x, gives A'(1,1), B'(2,3) and C'(2,1)

Therefore, the coordinates of the image are A'(1,1), B'(2,3) and C'(2,1).

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option