Farmer Smith Jr is putting together fruit baskets. He has 240 oranges and 150 grapefruits. What is the largest number of baskets he can put together so that he can have the same number of oranges in each basket and the same number of grapefruits in each basket? PLEASEE I NEED AN ANSWER

30 baskets

Step-by-step explanation:

To solve this question, we have to find the highest common divisor of 150 and 240

Let's list all the factors of 150;

1, 2, 3, 5, 6, 10, 15, 25, 30, 50, 75, 150

Factors of 240 are;

1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240

Looking at the factors gotten above, the highest common factor to both is 30.

Since there are 240 oranges, it means number of oranges in each basket would be 240/30 = 8 oranges per basket

Also, Since there are 150 grapefruits, it means number of oranges in each basket would be 150/30 = 5 grapefruits per basket

Thus, the oranges and grapefruits would have at most 30 baskets each for them to have the same number of fruits in each of their respective baskets.

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

v = 1/3 a^2h

step-by-step explanation:

if the height is 57.7cm and the height of the slant edge is 18.2cm, then the volume is 1/3 a^2h.