Which polynomials are in standard form?

options 2, 4 and 6

Step-by-step explanation:

standard form means there are no fraction coefficients, that they are ordered from greatest exponent to smallest, and by the letters of alphabet

1)

x^2*y^3+y^1+3x^1*y^2

should be x^2*y^3+3x^1*y^2+y^1

2) in standard form

3)

4x*y+2x^2*y^2+x*y^3

should be 2x^2*y^2+x*y^3+4x*y (if there are same exponents of x, put in order of decreasing y coefficients)

4) in standard form

5)

14b^3+a^1*b^3-6a^1*b^1+8a^1*b^2

should be a^1*b^3+8a^1*b^2-6a^1*b^1+a^0*14b^3 (14b^3 is last, since descending a exponents are the priority, and it has a^0 while rest have a^1)

6) in standard form

hello umm i don't understand your question can you explain it more pls

step-by-step explanation:

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)