![\boxed{ \frac{ \sqrt[3]{ {x}^{11} } }{4} }](/tpl/images/0683/2390/93602.png)
![= \frac{ {x}^{4} }{ \sqrt[3]{64x} } \\ \\ = \frac{ {x}^{4} }{ {(64x)}^{ \frac{1}{3} } } \\ \\ = \frac{ {x}^{4} }{ ({64}^{ \frac{1}{3} } )\times ({x}^{ \frac{1}{3} } )} \\ \\ = \frac{ {x}^{4} }{ ({( {4}^{3} )}^{ \frac{1}{3} }) \times( {x}^{ \frac{1}{3} } )} \\ \\ = \frac{ {x}^{4} }{ ({4}^{ \cancel{3} \times \frac{1}{ \cancel{3}} } ) \times( {x}^{ \frac{1}{3} } )} \\ \\ = \frac{ {x}^{4} }{4 {x}^{ \frac{1}{3} } } \\ \\ = \frac{ {x}^{4 - \frac{1}{3} } }{4} \\ \\ = \frac{ {x}^{ \frac{12 - 1}{3} } }{4} \\ \\ = \frac{ {x}^{ \frac{11}{3} } }{4} \\ \\ = \frac{ \sqrt[3]{ {x}^{11} } }{4}](/tpl/images/0683/2390/7d6cb.png)
Simplify this problem
...
Answers: 1
Another question on Mathematics
Mathematics, 21.06.2019 19:30
Lin is writing an equation to model the proportional relationship between y, the total cost in dollars of downloading videos from a website, and x, the number of videos downloaded. she knows that the total cost to download 3 videos was $12. her work to find the equation is shown below. joylin’s work step 1 k= 3/12= 0.25 step 2 y= 0.25x where did joylin make her first error?
Answers: 2
Mathematics, 22.06.2019 01:30
Meee i honestly dont know what this question talking about
Answers: 3
Mathematics, 22.06.2019 01:30
Which point does not lie on the graph k(x) = 8 -3 √x a. (-64, 12) b. (125, 3) c. (343, 1) d. (8, 5)
Answers: 2
You know the right answer?
Questions
Computers and Technology, 13.07.2019 20:00
Computers and Technology, 13.07.2019 20:00
Computers and Technology, 13.07.2019 20:00
Computers and Technology, 13.07.2019 20:00
Computers and Technology, 13.07.2019 20:00
History, 13.07.2019 20:00
History, 13.07.2019 20:00
Mathematics, 13.07.2019 20:00
History, 13.07.2019 20:00
Business, 13.07.2019 20:00
Computers and Technology, 13.07.2019 20:00
Computers and Technology, 13.07.2019 20:00
Mathematics, 13.07.2019 20:00
Computers and Technology, 13.07.2019 20:00
Computers and Technology, 13.07.2019 20:00
Computers and Technology, 13.07.2019 20:00
