A ball is thrown straight up with an initial velocity of 35.7 m/s. How long does it take to hit the ground?

y = v₀t - gt²/2

For y=0 (back to where we started),

0 = t(v₀ - gt/2)

t=0 (which we knew) or v₀ - gt/2 = 0

v₀ = gt/2

2v₀ = gt

t = 2v₀/g

t = 2 (35.7 m/s) / (9.8 m/s/s) = 7.3 seconds

7.3 seconds

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

answer: b)

step-by-step explanation:

its a dot plot because since the score is not high numbers.

- r3ktforgood ☕