Mr. Rodriguez is packing bags of snacks for his children's lunchboxes. If he has 20 blueberries and 30 grapes, what is the maximum number of bags of snacks that he can pack so that each bag has the same number of blueberries and grapes? 5 bags 10 bags 50 bags 60 bags

10 bags

Step-by-step explanation:

She has a total of 20 blueberries and 30 grapes and we are interested in knowing the total number of bags she can pack so each bag has the same number of blueberries and grapes.

In mathematical terms, what we are asked to

calculate here is the highest common factor of 20 and 30.

The highest common factor between 20 and 30 is 10

Now since she has 20 and 30 pieces of each fruit respectively, she can decide to place 2 per bag. Placing 2 per bag will mean that she will exhaust the bag of blueberries at the 20th blueberry and simultaneously exhaust the bag of grapes at the 20th grape also.

This leaves a net of 10 grapes. and 0 blueberries.

han when lo ahe whn hew anh ? ?

explanation:

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068