In ABC, mA = 46, mB = 105, and c = 19.8. Find a to the nearest tenth.

a = 29.3785

Step-by-step explanation:

Given ∠A = 46° and ∠B = 105°

we know that ∠A +∠B+∠C = 180°

                       46° + 105° +∠C = 180°

                      ∠C = 180 - 46 -105

                     ∠ C = 29°

By using sine rule

Given ∠A = 46° and  ∠ C = 29° and c = 19.8

on cross multiplication , we get

a = 29.3785

step-by-step explanation:

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation: