What is the vertex of the graph of the function f(x) = x2 + 8x - 2? (-4, 18)
(0, -2)
O (-8,-2)
O (-4, -18)

vertex = (- 4, - 18 )

Step-by-step explanation:

Given a parabola in standard form

f(x) = ax² + bx + c ( a ≠ 0 )

The the x- coordinate of the vertex is

= -

f(x) = x² + 8x - 2 ← is in standard form

with a = 1 and b = 8 , thus

= - = - 4

Substitute x = - 4 into f(x) for corresponding y- coordinate

f(- 4) = (- 4)² + 8(- 4) - 2 = 16 - 32 - 2 = - 18

vertex = (- 4, - 18 )

answer:     true

step-by-step explanation: