the straight line L has the equation 4y=5x+3. Point A has the coordinates (3,-2) Find the equation of the line straight line that is perpendicular to L and passes through A. Write your answer in the form y-mx+c where m and c are decimals or fractions {3 marks}

y = - x +

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 4y = 5x + 3 into this form by dividing the 3 terms by 4

y = x + ← in slope- intercept form

with slope m =

Given a line with slope m then the slope of a line perpendicular to it is

= - = - = - , thus

y = - x + c ← is the partial equation

To find c substitute (3, - 2) into the partial equation

- 2 = - + c ⇒ c = - 2 + =

y = - x + ← equation of perpendicular line

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18