PLEASE HELP ME. Really need help Find the features of the line 4y-3x = 108.

find:

x intercept

y-intercept

x intercept(y=0)

4y-3x=108

4×0-3x=108

-3x=108

x=108/-3

x=-36

y intercept(x=0)

4y-3×0=108

4y=108

y=108/4

y=27

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

it is not that hard all u have to do is plot the graph

step-by-step explanation: