The area of a right angled triangle is 600cm^.if base of the base of the exceeds the altitude by 10,find the dimensions of the triangle

b => base  => 40 cm

h => altitude => 30 cm

A = h*b/2

h=b-10

600=(b-10)b/2

600 = (b^2-10b)/2

1200=b^2-10b

b^2-10b-1200=0

(b-40)(b+30)=0

b=40 cm

h=b-10 = 40-10=30

answer: the first one

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