Five state officials are listed to the right. a. List the 10 possible samples (without replacement) of size 3 that can be obtained from the population of five officials. Governor (Upper G) Lieutenant Governor (Upper L) Secretary of State (Upper S) Representative (Upper R) Press Secretary (Upper P) b. If a simple random sampling procedure is used to obtain a sample of three officials, what are the chances that it is the first sample on your list in part (a)? the second sample? the tenth sample? a. List all 10 possible samples (without replacement) of size 3. Use the letter abbreviation for each official.

Possible samples:

(G,L), (G,S), (G,A), (G,P), (L,S), (S,A), (A,P), (L,P), (S,P), (A,L).

a) Given:

Population size .

Sample size

Possible sample (without replacement)

Governor, Lieutenant Governor, secretary of state, Attorney General, Press (P)

Possible samples:

(G,L), (G,S), (G,A), (G,P), (L,S), (S,A), (A,P), (L,P), (S,P), (A,L).

b) Event: choosing sample second and tenth.

The Probability of that it is the first sample.

Second and tenth sample

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All possible are:

(G,L,S)

(G,L,R)

(G,L,P)

(G,S,R)

(G,S,P)

(G,R,P)

(L,S,R)

(L,S,P)

(S,R,P)

{L,R,P)

Probability of 1st/2nd/10th sample = 1/10

Step-by-step explanation:

All the possible combinations of the 3 size samples from a 5 size population have been listed without repetition.

Total Numbers of Samples = 10

To find the probability of finding the first sample from random sampling procedure,

Probability = Number of desired outcomes/ Total number of outcomes

Where Number of desired outcome is 1 and total number of outcomes is 10.

Probability = 1/10

Similarly, to find 2nd sample or 10th sample, the number of desired outcomes is same i.e 1, hecne the probability remains the same i.e 1/10

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