Part 1. Find the missing sides for the 30-60-90 Triangles. Please show work

1. cos(30) = a/16

a = 16 x cos(30)

a = 8√3

sin(30) = c/16

c = 16 x sin(30)

c = 8

2. cos(30) = d/28

d = 28 x cos(30)

d = 14√3

sin(30) = f/28

f = 28 x sin(30)

f = 14

3. sin(30) = x/62

x = 62 x sin(30)

x = 31

cos(30) = y/62

y = 62 x cos(30)

y = 31√3

  1. (a, c) = (8, 8√3)

  2. (d, f) = (14, 14√3)

  3. (x, y) = (31, 31√3)

Step-by-step explanation:

Side lengths in a 30°-60°-90° triangle have the ratios 1 : √3 : 2. You can multiply these ratio values by an appropriate constant to make them match the lengths in your triangle.

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1. a : c : 16 = 1 : √3 : 2

Multiply by 16/2 = 8:

  = 8 : 8√3 : 16

  a = 8, c = 8√3

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2. d : f : 28 = 1 : √3 : 2

Multiply by 28/2 = 14:

  = 14 : 14√3 : 28

  d = 14, f = 14√3

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3. x : y : 62 = 1 : √3 : 2

Multiply by 62/2 = 31:

  = 31 : 31√3 : 62

  x = 31, y = 31√3

d is the answer

step-by-step explanation:

she will sew have sewn five dresses   and be 1/3 done with the sixth one in an hour.

step-by-step explanation:

3/4 of an hour=45 mins

lucy makes 1 dress per 11.25 minutes

45 mins+11.25 mins=56.25 mins

60 mins- 56.25 mins=3.75 mins

3.75 mins is 1/3 of of 11.25 mins

therefore she the other 1/3 would be part of the hour and she will have sewn 5 dresses and begun the sixth.

contact me if you have any questions you are welcome.