20 pts! Write an equation for the line passing through (1,9) AND perpendicular to 3x+7y=1
(a) in slope-intercept form
(b) in standard form

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

answer: 72: 111

step-by-step explanation:

ok thats very interesting