What is the factored form of 6x^2 + 13x + 6? (x + 4)(x + 9)
(2x + 3)(3x + 2)
(2x + 6)(3x + 1)
(6x + 1)(6x + 1)

I know the answer is B, but I don't know how. The factored form of the equation is:
6x^2 + 9x + 4x + 6. By using double grouping, I get:
(6x^2 + 9x) (4x + 6)
Then, with (6x^2 + 9x), I factor out an x. and end up getting (6x + 9). I can factor out a 3 from that, so I get (2x + 3).
Now, with (4x + 6), I factor out a 2, getting (2x + 3).
So, I'm not sure what I'm doing wrong, but I keep getting that the factored form of 6x^2 + 13x + 6 is (2x + 3)(2x + 3), not (2x + 3)(3x + 2)
If someone could please explain what my mistake is, it'd be greatly appreciated :-)