In the transmission of digital information, the probability that a bit has high, moderate, and low distortion is 0.02, 0.07, and 0.91, respectively. Suppose that three bits are transmitted and that the amount of distortion of each bit is assumed to be independent. Let and denote the number of bits with high and moderate distortion out of the three, respectively. Determine the following: A. fxy(x, y).
B. fx(x).
C. E(X).
D. Are X and Y independent?

A. (Table Attached)

B. (See Step 3)

C. 0.06 (See Step 4)

D. NOT independent (See Step 5)

Step-by-step explanation:

Name the probabilities:

p₁ = 0.02,   p₂ = 0.07,   p₃ = 0.91

q₁ = 1-p₁ = 0.98 ,   q₂ = 1-p₂ = 0.93 ,   q₃ = 0.09

Let X and Y be the number of bits with high and moderate distortion out of three.

A.

The function will follow multinomial distribution:

Substitute the values and make a table.

TABLE IN ATTACHMENT

B.

We calculate marginal distribution by:

∑

can be found by adding all the probabilities in each row for different value of X

For X=0 , ∑P = 0.94157441

For X=1 , ∑P = 0.057624

For X=2 , ∑P = 0.001176

For X=3 , ∑P =0.000008

The mathematic expectation E is the sum of product of each possibility with its probabiity.

∑

Find E(X):

Condition probability states:

It can also be written as:

Where = 0.057624

Calculate the quotient:

= 0 ,   = 0.862245

= 1 ,   = 0.132653

= 2 ,   = 0.000510

= 3 ,   = 0

Find the dependency:

We found that

= 0.862245

Calculate from summing the column from the table

Which are not equal.

Conclusion:

X and Y are NOT Independent

step-by-step explanation:

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p