A jar of quarters and dimes contains $20.00. There are 110 coins in all. How many of each are there?

There are 50 dimes and 110-50 = 60 quarters in the collection.

Step-by-step explanation:

Let D be the number of dimes.

Then the number of quarters is (110-D).

The "value equation" is

10D + 25*(110-D) = 2000.

Simplify and solve for D:

10D + 2750 - 25D = 2000,

-15D = 2000 - 2750,

-15D = -750,

D = %28-750%29%2F%28-15%29 = 50.

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: