Provide the value of k:
(2x-1)(kx+1)=6x^2-x-1

k = 3

Step-by-step explanation:

Expand the left side and compare the coefficients of like terms on both sides.

(2x - 1)(kx + 1) ← expand using FOIL

= 2kx² + 2x - kx - 1

Compare the coefficients of the x² term on both sides

2k = 6 ( divide both sides by 2 )

k = 3

idk what the heck he answer is, i’m just putting this here so i finish my account

the image is given below

since the options are not given so we draw it from the equation

the given equation is

y = (x-1) (x+4)

y = y² + 3x - 4

the above equation is a quadratic equation which will have two roots. if we draw the graph for it, it will look like this