1. If the ratio of the ages of Kissi and Esinam is 3:5 and that of Esinam and Lariba is 3:5 and the sum of the ages of all 3 is 147 years, what is the age difference between oldest the

youngest?

37 years difference.

Step-by-step explanation:

K = Kissi

k = Age of Kissi

E = Esinam

e = Age of Esinam

L = Lariba

l = Age of Lariba

k + e + l = 147

K : E

3 : 5 → (×3) → 12 : 15

E : L

3 : 5 → (×5) → 15 : 25

K : E : L

12 : 15 : 25

12 + 15 + 25 = 52

147/52 = 2.8269...

K is the young since out of the three part ratio, 12 is the smallest and likewise, L is the oldest.

k = 12 × 2.8269... = 33.923... → 34 y/o

e = 15 × 2.8269... = 42.40... → 42 y/o

l = 25 × 2.8269... = 70.673... → 71 y/o

∴ The difference between the youngest and oldest is:

71 - 34 = 37

5x+2x=49

7x=49

x=7. 35 apples

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?