A bug spray's effectiveness decreases over time. After h weeks, it retains only half of its effectiveness, and this trend continues. A function that represents this is Q(t) = 30•6^5-1

A scientist testing the bug spray tried to put the given equation into the form (t) = Q0(1/2)^t/h
where t is measured in years, but she got stuck. Her work is shown here.

Step 1 Q(t) = 30•6^5-t
Step 2 Q(t) = 30•6^5 •6^-t
Step 3 Q(t) = 233,280 - (1/6)^t
Step 4 Q(1) = 233,280•(1/6)^h•(t/h)
Step 5 Q(t) = 233,280 •((1/6)^h)•(t/h)
A: If (1/6)^h = 1/2, what is h to the nearest hundredth?