Complete the statements to solve for x. By the converse of the side-splitter theorem, if JK/KL = , then KM ∥ JN. ross-multiply: (x – 5)() = x(x – 3).
Distribute: x(x) + x(4) – 5(x) – 5(4) = x(x) + x(–3).
Multiply and simplify: x2 – x – = x2 – 3x.
Solve for x: x =

sorry not sure

step-by-step explanation:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

40 i don’t know lololol