Probability Race game Read the whole thing. Question 2 will be posted separately to make the question simple.

Question 1:
Why should you not play this game with Roland? Use probability to prove that
the game is unfair and Roland is likely to win. SHOW ALL YOUR WORK!

see below

Step-by-step explanation:

There are 36 possible outcomes when rolling 2 die

P( number) = number of times the sum appears / total outcomes

p(1) =0/36

P(2) = 1/36

p(3) = 2/36

p(4) = 3/36

p(5) = 4/36

p(6) = 5/36

p(7) = 6/36

p(8) = 5/36

p(9) = 4/36

p(10) = 3/36

p(11) = 2/36

p(12) = 1/36

Since he picked first he has the greatest odds so he is most likely to win

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)