La figura MNPQ es un rombo. Si 2θ – Φ =60°. Calcula el valor de “x”. Dime los fundamentos y principios que utilizas.

x = 30°

Step-by-step explanation:

Donde 2θ - Φ = 60 °, tenemos;

∠QMN = ∠QPM

Ф + ∠P / 2 + (180 - θ) = 180 (Suma de ángulos en un triángulo ΔQLP)

Por lo tanto, Ф + ∠P / 2 - θ = 0

Por lo tanto, ∠P / 2 = θ - Ф, también

270 ° + θ + x + ∠P / 2 = 360 (Suma de ángulos en un NOLP cuadrilátero) da

270 ° + θ + x + θ - Ф = 270 ° + 2 · θ - Ф + x = 360

Como 2 · θ - Ф = 60 °, tenemos;

270 ° + 60 + x = 360

x = 360 - 270 - 60 = 30 °

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.