Lim ((sin(pi(cosx)))/(x^2)) as x->0

Both the numerator and denominator approach 0, so by L'Hopital's rule

Using the fact that

we find

as , and , so the limit is π/2.

(I'm wondering if there's a way to do this without L'Hopital's rule, in case you haven't learned it yet...)

step- i d k and i d c : )

you: : 0

bye

step-by-step explanation: