Express (In 35+ln(1/7))/ In 25 in terms of In 5 and In 7

Properties of the logarithm: for any base of logarithm,

log(a*b) = log(a) + log(b)

If we replace b with 1/b, or b^-1, we have

log(a/b) = log(a) + log(1/b) = log(a) - log(b)

since

log(1/b) = log(b^-1) = - log(b)

using the power property of logarithms,

log(b^n) = n log(b)

Now,

ln35 = ln(5*7) = ln5 + ln7

ln(1/7) = - ln7

ln25 = ln(5^2) = 2 ln5

Putting everything together, we have

(ln35 + ln(1/7))/ln25 = (ln5 + ln7 - ln7)/(2 ln5) = ln5/(2 ln5) = 1/2

nlgqer

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