2 families go to the theatre. the p family of 2 adults and 3 children pay £46. the l family of 3 adults and 5 children pay £76. work out thecost of an adult ticket and child ticket.

child: 14

Adult : 2

Step-by-step explanation:

2A + 3C = 46eqn 1

3A + 5C = 76eqn 2

eqn 1 x 3 : 6A + 9C = 138 eqn 3

eqn 2 x 2: 6A + 10C = 152eqn 4

eqn 4 - eqn 3: 1OC - 9C = 152 - 138

1C = 14

subst 1C = 14 into eqn 1

2A + 3(14) = 46

2A = 46 - 42

2A = 4

1A = 2

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages