Solve Systems of Algebraic Equations in Two Variables Hello I need some help on setting up 2 equations of this problem. The answers are cheeseburger costs $1.55 and the milkshake $0.85

Four cheeseburgers and two chocolate milkshakes cost a total of $ 7.90. Two
Shakes cost 15 cents more than a hamburger with
cheese so What is the price of a cheeseburger?
And the price of a shake?

4c+ 2m = 7.90

2m -.15 = c

Step-by-step explanation:

Let c = cheese burger

m = milkshake

4c+ 2m = 7.90

2m -.15 = c

Substitute into the first equation

4( 2m -.15) +2m = 7.90

Distribute

8m -.6 +2m = 7.90

Combine like terms

10m - .6 = 7.90

Add .6 to each side

10m = 7.90+.6

10m = 8.50

Divide by m

10m = 8.50/10

m = .85

Now find c

2m -.15 = c

2(.85) - .15=c

1.70-.15 = c

1.55 =c

range is infinite on both x and y axis positive and negative

step-by-step explanation:

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: