An old bone contains 80% of its original ca 14. Use the half-life model to find the age
bone. Find an equation equivalent

An old bone contains 80% of its original carbon-14 in 1844.6479 years

Step-by-step explanation:

We know that half life time of C-14 is 5730 years so, h=5730

now, we can use formula we can plug back h and we get

An old bone contains 80% of its original carbon-14

so, P(t)=0.80Po we can plug it and then we solve for t

So, An old bone contains 80% of its original carbon-14 in 1844.6479 years

2

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1