Which linear equation includes the points
(6,0) and
(0, – 4)?

y= (2/3)x - 4

Step-by-step explanation:

To answer this you'll want to use the slope intercept form of a line:

y= mx + b

So to solve essentially you just have to find the values for m and b

- m represents the slope of the line

- b is the y-intercept (the point where the line crosses the y-axis)

You can figure that b = -4 because the line will cross the y-axis when x = 0, and you are given the point on the line (0,-4), where x is equal to 0.

Now to find the slope of the line, since you are given two points on the line you will want to use the slope equation:

slope =

So you can assign each of the two points a number (1 or 2) where its values are equal to (x1, y1) or (x2, y2). It does not matter which point gets which number.

In this example:

We will assign the point (6,0) to be (x1, y1),

and we will assign the point (0, -4) to be (x2, y2)

So we end up with the following:

m=

m=  

m=  

Simplify the fraction:

m =

From there you just substitute in for m and b into the slope intercept equation

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !