I dare you to solve this!Foil method

a^(2m) + 2 a^m b^ (n-1) + b^ ( 2n -2)

Step-by-step explanation:

( a^m + b^(n-1) )( a^m + b^(n-1) )

FOIL

first: a^m a^m = a^ 2m

outer: a^m b^ n-1

inner a^m b^ n-1

last : b^ n-1  b^ n-1 = b^ ( 2n -2)

Add together

a^(2m) + 2 a^m b^ (n-1) + b^ ( 2n -2)

should have been evaluated with one odd value and one even value. the expressions have equivalent values when . when , the first expression has a value of 3 and the second

step-by-step explanation: