The final velocity, V, of an object under constant acceleration can be found using the formula v2=v2+2as, where v is the initial velocity (in meters per second), a is acceleration (in meters per second), and s is the distance (in meters). What is the formula solved for a?

a = (V^2 - v^2)/2s

Step-by-step explanation:

The equation for the final velocity is:

V^2 = v^2 + 2*a*s

where V is the final velocity, v is the initial velocity, a is the acceleration and s is the distance.

Now, we want to solve this formula for a, this would mean isolate a in one side of the equation, this is pretty simple, first we pass subtract v^2 in both sides.

V^2 - v^2 = v^2 + 2*a*s - v^2

V^2 - v^2 = 2*a*s

now we can divide by 2*s in both sides:

(V^2 - v^2)/2s = 2*a*s/2s = a

a = (V^2 - v^2)/2s

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column