George is given two circles, Circle O and circle X, as shown. If he wants to prove that the two circles are similar, what would be the correct second step in his proof? Given: The radius of circle O is r, and the radius of circle X is r'. Prove: Circle O is similar to circle X.

answer is A - C = 2-pi-r/C = 2-pi-r and C/C = r/r by the division property of equality

Step-by-step explanation:

on  A P E X

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

x/3-10=8

x/3=18

x=48