On a coordinate plane, a line goes through (0, negative 3) and (3, negative 2). A point is at (negative 4, 2). Find the equation of the line parallel to line h that passes through (–4, 2).

y = one-third x + StartFraction 10 Over 3 Endfraction
y = negative one-third x + two-thirds
y = 3x + 14
y = –3x – 10

Correct option: first one -> y = (1/3)x + (10/3)

Step-by-step explanation:

The linear function that represents a line is:

y = ax + b

Where a is the slope and b is the y-intercept.

First we need to find the slope of the line that goes through (0, -3) and (3, -2).

Using both points, we can find the equation of the line:

x = 0 -> y = -3

-3 = a*0 + b

b = -3

x = 3 -> y = -2

-2 = 3a - 3

3a = 1

a = 1/3

The parallel line needs to have the same slope as the line, so we can model the parallel line with the following equation:

y = (1/3)x + b

The parallel line goes through the point (-4, 2), so we have:

x = -4 -> y = 2

2 = (1/3)*(-4) + b

b = 2 + (4/3)

b = 10/3

So the equation of the parallel line is:

y = (1/3)x + (10/3)

Correct option: first one

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation: