M∠LONm, angle, L, O, N is a straight angle. \qquad m \angle LOM = 7x - 92^\circm∠LOM=7x−92
∘
m, angle, L, O, M, equals, 7, x, minus, 92, degrees
\qquad m \angle MON = 6x + 12^\circm∠MON=6x+12
∘
m, angle, M, O, N, equals, 6, x, plus, 12, degrees
Find m\angle LOMm∠LOMm, angle, L, O, M:

G(x)=x2-16xb=-16, so =16 = 649(x) = (x2 - 16x + 64) - 649(x) = (x - 1)2-

To find the extreme values of a function f(x.y) on a curve x-x(t), y y(t), treat f as a function of the single variable t and use the chain rule to find where df/dt is zero. in any other single-variable case, the extreme values of f are then found among the values at the critical points (points where df/dt is zero or fails to exist), and endpoints of the parameter domain. find the absolute maximum and minimum values of the following function on the given curves. use the parametric equations x=2cos t, y 2 sin t functions: curves: i) the semicircle x4,y20 i) the quarter circle x2+y-4, x20, y20 b, g(x,y)=xy

Why did the ice arena get so hot after the big game (this is math related google it to find the paper