A company produces steel rods. The lengths of all their steel rods are normally distributed with a mean of 155.1-cm and a standard deviation of 2.2-cm. For shipment, 11 steel rods are bundled together. Find the probability that the average length of a randomly selected bundle of steel rods is between 155.6-cm and 156.2-cm.

The probability that the average length of a randomly selected bundle of steel rods is between 155.6-cm and 156.2-cm

P(155.6 < x⁻ < 156.2) = 0.174 cm

Step-by-step explanation:

Given sample size 'n' = 11 steel rods

Mean of the Population = 155.1 cm

Standard deviation of the Population = 2.2 cm

Given x⁻ be the random variable of Normal distribution

Let x₁⁻ =  155.6 cm

Let  x₂⁻ =  156.2 cm

The probability that the average length of a randomly selected bundle of steel rods is between 155.6-cm and 156.2-cm.

P(x⁻₁ < x⁻ <x⁻₂) = P(Z₁ < Z <Z₂)

                       = P(Z <Z₂) - P(Z<Z₁)

                      = 0.5 +A(1.629) - (0.5 +A(0.7541)

                      = A(1.629) - A(0.7541)

                      = 0.4474 - 0.2734

                      = 0.174

Conclusion:-

The probability that the average length of a randomly selected bundle of steel rods is between 155.6-cm and 156.2-cm = 0.174

1 1/7 hope i

step-by-step explanation:

8/7 = (1 * 7 + 1) / 7 = 1 + 1/7 = 1 1/7

what are you doing do you need examples of variable questions?

step-by-step explanation:

5a-1=9               bring the one over the =

5a=10                     divide by your variable

a=2

brainliest? ?

here try this one

3a-24=0