Solve the following system of equations:

x + 3y = −4
x + 5y = −6

pls and thx

x = -1  y = -1

Step-by-step explanation:

x + 3y = −4

x + 5y = −6

Multiply the first equation by -1

-x - 3y = 4

The add to the second equation to eliminate x

-x - 3y = 4

x + 5y = −6

 2y = -2

Divide by 2

2y/2 = -2/2

y = -1

Now solve for x

x+3y = -4

x +3(-1) = -4

x -3 = -4

Add 3 to each side

x-3+3 = -4+3

x = -1

work is pictured and shown

i'm sorry mate, but i am not seeing any figures. i am unable to solve this for you.

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)