Which of the following equations is equivalent to S = pi r squared h?

B. h=S/πr²

Step-by-step explanation:

The question lacks options. Here is the complete question.

Which of the following equations is equivalent to S = πr²h

a. h=S-πr^2

b. h=S/πR^2

C. h= πr^2/S

D. h=S+ πr^2

To know the equation equivalent to πr²h, we will make h the subject of the formula as shown from the one given in equation.

S = πr²h

To get h, we will divide both sides by the coefficient of h (i.e πr²)

S/πr² = πr²h/πr²

S/πr² = h

h = S/πr²

This shows that h = S/πr² is equivalent to S = πr²h

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3