PLEASE HELP ASAP I always give brainliests! You have found the following ages (in years) of 4 bears. Those bears were randomly selected from the 22 bears at your local zoo: 5,4,6,39 Based on your sample, what is the average age of the bears? What is the standard deviation? Round your answers to the nearest tenth.
Average age: years old
Standard deviation: years

first to find average age add all the ages divide by number of ages 4

5+4=9

9+6=15

15+39=54

54/4=13.5

For standard deviation find the mean/average

13.5

then subtract the mean from each number/age

5-13.5=-8.5

4-13.5=-9.5

6-13.5=-7.5

39-13.5=25.5

then square each number

-8.5^2=-72.25

-9.5^2=-90.25

-7.5^2=-56.25

25.5^2=650.25

then find the mean/average of the new numbers

-72.25+-90.25+-56.25+650.25=431.5

431.5/4=107.85

then take the square root of the new mean/average

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a

df =

both have same length