Which equation is equivalent to the following? 2x^2 – 12x + 2y^2 + 20y – 28 = 0
1) 2(x-3)^2+2(y+5)^2=44
2) 2(x-3)^2+2(y+5)^2=60
3) 2(x-3)^2+2(y+5)^2=62
4) 2(x-3)^2+2(y+5)^2=96

4)  2(x - 3)^2 + 2(y + 5)^2 = 96.

Step-by-step explanation:

2x^2 – 12x + 2y^2 + 20y – 28 = 0

2(x^2 – 6) + 2(y^2 + 10y) = 28

2 ( (x - 3)^2 - 9)) + 2((y + 5)^2 - 25) = 28

2(x - 3)^2 - 18 + 2(y + 5)^2  - 50 = 28

2(x - 3)^2 + 2(y + 5)^2 = 28 + 18 + 50

2(x - 3)^2 + 2(y + 5)^2 = 96

Step-by-step explanation:

It basically represents a circle.

Equation of circle

Organize the variables

Now we have to complete the square for both groups:

Now, I would proceed with:

We got the center and the circle radius

But this is not what you want:

So, just multiply both sides by 2 and you'll get:

f(x) = y

f(-3) = -5

step-by-step explanation: